# Simple Harmonic Motion

### If an object is free to oscillate around an equilibrium point and experiences a linear restoring Force, it performs a motion which we refer to as 'Simple Harmonic Motion'.

If an object is free to oscillate around an equilibrium point and experiences a linear restoring Force, it performs a motion which we refer to as 'Simple Harmonic Motion'.

### In order for an object to display simple harmonic motion (SHM), two key factors must be met.

In order for an object to display simple harmonic motion (SHM), two key factors must be met.

### It must:-

It must:-

### 1. Store Potential Energy in some form

1. Store Potential Energy in some form

### 2. Have mass in order to possess Kinetic Energy

2. Have mass in order to possess Kinetic Energy

### The most simple example of an object undergoing Simple Harmonic Motion is a mass suspended from a coiled spring :-

The most simple example of an object undergoing Simple Harmonic Motion is a mass suspended from a coiled spring :-

### In the above diagram, the mass is caused to oscillate by being pulled down and released. When the mass is moved away from the equilibrium point, energy is stored as elastic potential energy within the Spring.

In the above diagram, the mass is caused to oscillate by being pulled down and released. When the mass is moved away from the equilibrium point, energy is stored as elastic potential energy within the Spring.

### For a spring following this type of motion :-

For a spring following this type of motion :-

### There is always an unbalanced Force acting on the mass (except when passing the equilibrium point)

There is always an unbalanced Force acting on the mass (except when passing the equilibrium point)

### This Force is always in the opposite direction to the motion of the Mass

This Force is always in the opposite direction to the motion of the Mass

### These two factors apply to all objects undergoing Simple Harmonic Motion.

These two factors apply to all objects undergoing Simple Harmonic Motion.

### We call the opposing Force, the restoring Force.

We call the opposing Force, the restoring Force.

### The video below gives a summary of Simple Harmonic Motion, whilst giving demonstrations of several experiments

The video below gives a summary of Simple Harmonic Motion, whilst giving demonstrations of several experiments

## Defining Simple Harmonic Motion

Defining Simple Harmonic Motion

### The following is the standard written definition of Simple Harmonic Motion.

The following is the standard written definition of Simple Harmonic Motion.

### "When an object is displaced from its equilibrium or rest position, and the unbalanced Force is proportional to the Displacement of the object and acts in the opposite direction, the motion is said to be Simple Harmonic. "

"When an object is displaced from its equilibrium or rest position, and the unbalanced Force is proportional to the Displacement of the object and acts in the opposite direction, the motion is said to be Simple Harmonic. "

## Force against Displacement

Force against Displacement

### As seen in the statement above, the unbalanced Force experienced by the Mass undergoing SHM is proportional to the Displacement. If this Force is measured experimentally, then the following graph can be generated :-

As seen in the statement above, the unbalanced Force experienced by the Mass undergoing SHM is proportional to the Displacement. If this Force is measured experimentally, then the following graph can be generated :-

### As can been seen above, the graph shows also that the force acts in the opposite direction to the displacement. By introducing a Force constant, we can generate the following :-

As can been seen above, the graph shows also that the force acts in the opposite direction to the displacement. By introducing a Force constant, we can generate the following :-

### where :-

where :-

### F = The restoring Force ( N )

F = The restoring Force ( N )

### k = The Force constant ( Nm^{-1} )

k = The Force constant ( Nm

^{-1})

### x = The Displacement ( m )

x = The Displacement ( m )

### Note - The negative sign in the formula shows that the Force acts in the opposite direction to the displacement.

Note - The negative sign in the formula shows that the Force acts in the opposite direction to the displacement.

### The video below gives a brief overview of Hookes Law and how it applies to springs in SHM

The video below gives a brief overview of Hookes Law and how it applies to springs in SHM

## SHM in terms of Acceleration

SHM in terms of Acceleration

### By equating the above formula with Newton's Second Law, we can derive a relationship for Acceleration :-

By equating the above formula with Newton's Second Law, we can derive a relationship for Acceleration :-

## Example 1 -

Example 1 -

### A 1.0 kg mass attached to a horizontal spring ( k = 5.0 Nm^{-1} ) is performing SHM on a horizontal, frictionless surface. What is the Acceleration of the Mass when its displacement is 4.0 cm ?

A 1.0 kg mass attached to a horizontal spring ( k = 5.0 Nm

^{-1}) is performing SHM on a horizontal, frictionless surface. What is the Acceleration of the Mass when its displacement is 4.0 cm ?

### a = ?

a = ?

### k = 5.0 Nm^{-1}

k = 5.0 Nm

^{-1}

### m = 1.0 kg

m = 1.0 kg

### x = 4.0 cm = 0.04 m

x = 4.0 cm = 0.04 m

### a = - ( 5.0 / 1.0 ) x 0.04

a = - ( 5.0 / 1.0 ) x 0.04

### a = -0.2 ms^{-2}

a = -0.2 ms

^{-2}

### The above calculation is based on a spring ( with a spring constant = k ) obeying Hooke's Law, but in order to apply our understanding of SHM universally, we must convert this into general terms.

The above calculation is based on a spring ( with a spring constant = k ) obeying Hooke's Law, but in order to apply our understanding of SHM universally, we must convert this into general terms.

### In general terms the constant ( k / m ) is related to the period of the motion by :-

In general terms the constant ( k / m ) is related to the period of the motion by :-

### giving the general formula for acceleration in SHM as :-

giving the general formula for acceleration in SHM as :-

### Note - Omega in this case is Angular Frequency , whereas in unit one (Rotational Dynamics), we used the same symbol for Angular Velocity when working with circular motion. This is because the two concepts are very much related, as will be shown below.

Note - Omega in this case is Angular Frequency , whereas in unit one (Rotational Dynamics), we used the same symbol for Angular Velocity when working with circular motion. This is because the two concepts are very much related, as will be shown below.

## Equations of Motion and SHM

Equations of Motion and SHM

### For ease of explanation, we can compare on object undergoing SHM with an object moving in a circle.

For ease of explanation, we can compare on object undergoing SHM with an object moving in a circle.

### Consider an object Q travelling with a constant linear speed (v) anti-clockwise around the circle above. If we project a line from Q to the vertical axis we can find its vertical displacement on the Y axis (line OP).

Consider an object Q travelling with a constant linear speed (v) anti-clockwise around the circle above. If we project a line from Q to the vertical axis we can find its vertical displacement on the Y axis (line OP).

### The Displacement on the vertical axis is equal to :-

The Displacement on the vertical axis is equal to :-

### By differentiation, an equation of the Velocity can be obtained :-

By differentiation, an equation of the Velocity can be obtained :-

### Note - Differentiation of Trig Identities can be found within the CfE Higher Maths course

Note - Differentiation of Trig Identities can be found within the CfE Higher Maths course

### By further differentiation, the acceleration can also be found :-

By further differentiation, the acceleration can also be found :-

### By combining the two equations above and by using the trig identity below, the following can be derived :-

By combining the two equations above and by using the trig identity below, the following can be derived :-

### The above formula allows you to predict the velocity at any given point in Simple Harmonic Motion.

The above formula allows you to predict the velocity at any given point in Simple Harmonic Motion.

## Specific points of importance in SHM

Specific points of importance in SHM

### By looking at specific points in the oscillation, it can be shown that there are obvious points at which the acceleration will be at a maximum and the other points at which the velocity will be at maximum.

By looking at specific points in the oscillation, it can be shown that there are obvious points at which the acceleration will be at a maximum and the other points at which the velocity will be at maximum.

### Velocity - v^{2} = w^{2} (A^{2} - y^{2})

Velocity - v

^{2}= w

^{2}(A

^{2}- y

^{2})

### By analysis of the above formula, it can be shown that V is at a maximum when Displacement is equal to zero.

By analysis of the above formula, it can be shown that V is at a maximum when Displacement is equal to zero.

### Acceleration - a = -w^{2} y

Acceleration - a = -w

^{2}y

### By analysis of the above formula, it can be shown that a is at a maximum when displacement is equal to the amplitude.

By analysis of the above formula, it can be shown that a is at a maximum when displacement is equal to the amplitude.

## Graphical Analysis of SHM

Graphical Analysis of SHM

### The following graphs show how SHM can be seen graphically :-

The following graphs show how SHM can be seen graphically :-

### Displacement -

Displacement -

### Velocity -

Velocity -

### Acceleration -

Acceleration -

### The particular equation used for each motion depends on the starting conditions. this means that if :-

The particular equation used for each motion depends on the starting conditions. this means that if :-

### y = 0 at t = 0 y = A Sin wt

y = 0 at t = 0 y = A Sin wt

### y = A at t = 0 y = A Cos wt

y = A at t = 0 y = A Cos wt

### Note - for assessment, you must be able to show by differentiation how both the sin and cos variant can be used to find velocity and acceleration.

Note - for assessment, you must be able to show by differentiation how both the sin and cos variant can be used to find velocity and acceleration.

## Example 1 -

Example 1 -

### An object is vibrating with Simple Harmonic Motion of amplitude 0.02 m and a frequency of 5.0 Hz. Assume that at t = 0, y = 0 and that the motion starts in the positive y direction.

An object is vibrating with Simple Harmonic Motion of amplitude 0.02 m and a frequency of 5.0 Hz. Assume that at t = 0, y = 0 and that the motion starts in the positive y direction.

### 1. Calculate the maximum values of the Velocity and Acceleration

1. Calculate the maximum values of the Velocity and Acceleration

### 2. Calculate the Velocity and Acceleration when Displacement is equal to 0.008 m

2. Calculate the Velocity and Acceleration when Displacement is equal to 0.008 m

### Find the Time taken for the object to move from an equilibrium position to a Displacement of 0.012 m

Find the Time taken for the object to move from an equilibrium position to a Displacement of 0.012 m

## Simple Pendulum as SHM proof

Simple Pendulum as SHM proof

### The following diagram shows a simple pendulum undergoing Simple Harmonic Motion as well as the Forces acting upon it

The following diagram shows a simple pendulum undergoing Simple Harmonic Motion as well as the Forces acting upon it

### Note - assumptions made

Note - assumptions made

### 1. Inextensible string of length L

1. Inextensible string of length L

### 2. Negligible Mass string

2. Negligible Mass string

### In the case of the pendulum above, the restoring Force is equal to the component of the Weight acting towards the centre - F = - mg Sinq

In the case of the pendulum above, the restoring Force is equal to the component of the Weight acting towards the centre - F = - mg Sinq

### If the angle is small ( less than ~ 10^{o}_{ } ) then sinq = q in radians and therefore q = x / L

If the angle is small ( less than ~ 10

^{o}

_{ }) then sinq = q in radians and therefore q = x / L

### Therefore if the above relationship is shown to be true experimentally, the simple pendulum does follow Simple Harmonic Motion.

Therefore if the above relationship is shown to be true experimentally, the simple pendulum does follow Simple Harmonic Motion.